These should be simple questions...

[Nick_the_'Nole]

...but no amount of searching will turn up a straight answer. And sorry if this is a little bit more on the DIY side, but I figured I might get better answers from the antique radio guys.

I am trying to build a battery eliminator for an old Atwater Kent 30. Theoretically simple enough, yet I can't seem to make heads or tails of it. First of all, how in bloody hell are you supposed to hook this thing up? I got that the A+ supply is 5v, the B+ is +90v, then you have a +67.5v and a +22.5v, and a -4.5v C bias as well. No problem there. But the A- lead is also labelled B- and C+? WTF, how are you supposed to hook that up?

Basically I need to know what all this translates to in building an AC ps for the thing. Right now I'm thinking I just need a + and - filament hookup (with the - just being a return to ground in the PS), a + for each of the plate supplies, and a - for the bias (possibly even just a lead hooked to the - side of a battery)?

Also, for the higher voltage supplies, would it be wise to just run voltage dividers directly off rectified/filtered wall power? If so, what kind of current draw am I looking at on those?, since resistor values are dependent on that bit of info and it is nowhere to be found...